Saturday, February 20, 2010

Hardy-weinberg Problems And Answers Lab 8 Ap Bio Lab 8?

Ap bio lab 8? - hardy-weinberg problems and answers lab 8

Can someone explain to me the answers to the problems of Hardy-Weinberg in the AP bio lab 8 and how? I am first, but no other work for me!

1 comment:

ATP-Man said...

1. In Drosophila, the allele for normal length wings is dominant over the allele for vestigial wings. In a population of 1,000 people, 360 have the recessive phenotype. How many people should be homozygous dominant and heterozygous for this character?

360 are recessive, which means that 36% of the population. that the square root to obtain and the frequency of 6 years.
subtract the increase of 1 and 4 p.
p + q = 1 .6 + .4 = 1

P2 2 pq + q2 = 1

.16 .48 .36

160 480 360 = 1000

2. The allele's ability, language is dominant over the allele contrary, without this ability. In a population of 500 people, 25% show the recessive phenotype. How many peopleDid they expect that homozygous dominant and heterozygous for this character?

p + q = 1-recessive = square root of 25%, 25 and get 5

.5 + .5 = 1

p2 + 2pq + q2 = 100

.25 + .50 + .25 = 100

125 + 250 + 125 = 500

3. The allele for the hair, bit pattern, which is known as "Widow's Peak" on the allele for non-peak "widow dominant. In a population of 1,000 people, 510 were the dominant phenotype. How many people have for each of the three possible genotypes for this character to be expected?

510 profile to the dominant 490-recessive.

The remaining 49% of the population. Square root of 49 and 7 are, as the frequency of the recessive allele.

p + q = 1.3 + .7 = 1

P2 2 pq + q2 = 1

.09 + .42 + .49 = 1

46 + 214 + 250 = 510

4. For some people, takes the dominant expression of a particular attribute 91% of the time. What is the frequency of the dominant allele?

So 9% is a recession. 09 and 0.3 root for the recessive frequency. 0.7 is the answer.

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